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Patrick Louys 2016-11-01 16:26:05 +01:00 committed by GitHub
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07-inversion-of-control.md
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@ -2,11 +2,11 @@
### Inversion of Control
In the last part you have set up a controller class and generated output with `echo`. But let's not forget that you have a nice object oriented HTTP abstraction available. But right now it's not accessible inside your class.
In the last part you have set up a controller class and generated output with `echo`. But let's not forget that we have a nice object oriented HTTP abstraction available. But right now it's not accessible inside your class.
The sane option is to use [inversion of control](http://en.wikipedia.org/wiki/Inversion_of_control). This means that instead of giving the class the responsiblity of creating the object it needs, you just ask for them. This is done with [dependency injection](http://en.wikipedia.org/wiki/Dependency_injection).
If it sounds a little complicated right now, don't worry. Just follow the tutorial and once you see how it is implemented things will make more sense.
If this sounds a little complicated right now, don't worry. Just follow the tutorial and once you see how it is implemented, it will make sense.
Change your `Homepage` controller to the following:
@ -33,11 +33,11 @@ class Homepage
}
```
Note that you are [importing](http://php.net/manual/en/language.namespaces.importing.php) `Http\Response` at the top of the file. This means that whenever you use `Response` inside this file, it will resolve to the fully qualified name.
Note that we are [importing](http://php.net/manual/en/language.namespaces.importing.php) `Http\Response` at the top of the file. This means that whenever you use `Response` inside this file, it will resolve to the fully qualified name.
In the constructor you are now explicitly asking for a `Http\Response`. In this case, `Http\Response` is an interface. So any class that implements the interface can be injected. See [type hinting](http://php.net/manual/en/language.oop5.typehinting.php) and [interfaces](http://php.net/manual/en/language.oop5.interfaces.php) for reference.
In the constructor we are now explicitly asking for a `Http\Response`. In this case, `Http\Response` is an interface. So any class that implements the interface can be injected. See [type hinting](http://php.net/manual/en/language.oop5.typehinting.php) and [interfaces](http://php.net/manual/en/language.oop5.interfaces.php) for reference.
Now the code will result in an error because you are not actually injecting anything. So let's fix that in your `Bootstrap.php` where you dispatch when a route was found:
Now the code will result in an error because we are not actually injecting anything. So let's fix that in the `Bootstrap.php` where we dispatch when a route was found:
```php
$class = new $className($response);